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Show that 12 n cannot end with zero or 5

WebJan 18, 2024 · See answer. 12 to the power n cannot end with the digit 0 or 5 because for a number to end with the digit 0 or 5,it should have 2 and 5 both in its prime factorization. … WebGrievance procedure mor mortgage broker mentorship program/title ...

8. Show that 12n cannot end with the digit 0 or 5 for any natural number n.

WebMar 29, 2024 · Let us take the example of a number which ends with the digit 0 So, 10 = 2 × 5 100 = 2 × 2 × 5 × 5 Here we note that numbers ending with 0 has both 2 and 5 as their prime factors Whereas 4n = (2 × 2) n Does not have 5 as a prime factor. So, it does not end with zero. Therefore, 4n cannot end with zero for any natural number n WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 … how many square feet in empire state building https://2brothers2chefs.com

Show that 12n cannot end with the digit 0 or 5 for any natural …

WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3n WebJun 8, 2015 · 12n can only end with digits 0 or 5 when it base prime factors include 2 and 5 as its factors. but 12 has not 2 and 5 as its prime factors . so it is impossible for 12n to end with the digit 0 or 5 Advertisement Still have questions? Find … WebFor a number to end with 0, the number must have 2 & 5 as factors. 10=2×5 100=2 2×5 2 For a number to end with 5, the number must have 5 as a factor. 30=5×6 3 n×(2 2) m=3 n×2 2m This number dosent have 5 or 5 and 2 as its factors. Therefore the number cant end with 0 o 5. Was this answer helpful? 0 0 Similar questions how many square feet in double roll wallpaper

NCERT Exemplar Class 10 Maths Chapter 1 Real Numbers

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Show that 12 n cannot end with zero or 5

Show that (12)n cannot end with digit

WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be … WebIf any number ends with the digit 0 that means it should be divisible by 5. That is, if 6 n ends with the digit 0, then the prime factorisation of 6 n would contain the prime number 5. Prime factors of 6 n = (2 × 3) n = (2) n × (3) n. We can clearly observe, 5 is not present in the prime factors of 6 n. That means 6 n will not be divisible by 5.

Show that 12 n cannot end with zero or 5

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WebApr 11, 2024 · 4.3K views, 492 likes, 148 loves, 70 comments, 48 shares, Facebook Watch Videos from NET25: Mata ng Agila International April 11, 2024 WebSolution. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12 n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n …

WebShow that 12 n cannot end with the digit 0 or 5 for any natural number n. Answers (1) We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5. Here 12n … WebNov 2, 2024 · To show that 12^n cannot end with 0 or 5 for any natural number n. Explanation: 12 ^n in prime factor form cn be written as, As, there is no term in the factor …

WebApr 21, 2024 · For a number to be end with digit zero its prime factors must have atleast one 2 and A are 5 both and for a number to be end with 5 its prime factors must have at least … WebSolution. If any number ends with the digit 0 or 5. It is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of …

WebShow that (12) n cannot end with digit 0 or 5 for any natural number n. Answers (1) There is no factor of the form 5 n, therefore, 12 n can not end with digit 0 or 5 for any natural …

how many square feet in buckingham palaceWebAug 8, 2024 · Here `" " 12 = 2 xx 2 xx 3` `= 2^(2) xx 3` `rArr" " 12^(n) = (2^(2) xx 3)^(n) = 2^(2n) xx 3^(n)` We know that if any numbers ends with the digits 0 or 5, its is always divisible by 5. But the prime factorisation of `12^(n)` does not contain the prime number 5. Hence, `12^(n)` cannot end with the digits 0 or 5 for any natural number n. how did sundiata turn mali into an empireWebHere, Number=12 n where n stand for any natural number . Now 12 n = (2 2 x3) n. Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to … how did sum 41 get their name